Exercise 9. Explain why
9 (a). holds
for all z.
Solution 9 (a).
See text and/or instructor's solution manual.
formula (5-1) .
We are done.
II. Use the Definition
And substitute into this and get
Recall Exercise 6 in Section 4.1 where we proved: If then .
Setting and and applying this result yields
Combining the above finishes our proof
for Solution. Method
II. Let , then .
It follows that
We are really done.
Aside. We can let Mathematica double check our work.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell